Simple Harmonic Motion
Oscillations • Class 11 Physics • NCERT • CBSE
SHM: x = A sin(ωt + φ). Velocity v = Aω cos(ωt + φ). Acceleration a = −ω²x. Time period of spring T = 2π√(m/k). Time period of simple pendulum T = 2π√(l/g). Total energy E = ½kA² = constant.
Key Formulas
x = A sin(ωt + φ)v = ω√(A² − x²)a = −ω²xT = 2π√(m/k) (spring)T = 2π√(l/g) (pendulum)E = ½kA² (total energy)
Frequently Asked Questions
- What is the condition for SHM?
- The restoring force (or acceleration) must be proportional to displacement from mean position and directed towards it: a = −ω²x.
- Does mass affect the time period of a simple pendulum?
- No. T = 2π√(l/g). The period depends only on the length and gravitational acceleration, not on mass.
- What is the total energy in SHM?
- E = ½kA² = constant. It equals ½mω²A². KE and PE interchange, but their sum remains constant.
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