Mole Concept and Molar Mass
Some Basic Concepts of Chemistry • Class 11 Chemistry • NCERT • CBSE
One mole of any substance contains 6.022 × 10²³ particles (Avogadro's number). Molar mass is the mass of one mole of a substance in grams (numerically equal to its molecular/atomic mass in amu). n = m/M where n = moles, m = mass in grams, M = molar mass.
Key Formulas
n = m/MN = n × 6.022 × 10²³V(STP) = n × 22.4 L% element = (mass in 1 mol / M_compound) × 100
Frequently Asked Questions
- What is Avogadro's number and why is it important?
- Avogadro's number Nₐ = 6.022 × 10²³ mol⁻¹ is the number of elementary entities (atoms, molecules, ions) in one mole of any substance. It bridges the microscopic world (atoms) with the macroscopic world we measure in grams. It was determined from experiments involving diffraction and electrolysis.
- What is the difference between empirical and molecular formula?
- Empirical formula gives the simplest whole-number ratio of atoms in a compound (e.g., CH₂O for glucose). Molecular formula gives the actual number of each atom in one molecule (e.g., C₆H₁₂O₆ for glucose). Molecular formula = n × empirical formula, where n = molecular mass ÷ empirical formula mass.
- How do you calculate moles at STP?
- At STP (Standard Temperature 0°C, Pressure 1 atm), 1 mole of any ideal gas occupies 22.4 L (molar volume). So moles of gas = Volume (L) / 22.4. Example: 5.6 L of CO₂ at STP = 5.6/22.4 = 0.25 mol of CO₂.
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