Surface Areas and Volumes • Class 10 Mathematics • NCERT • CBSE
Class 10 extends Class 9 solid geometry to combinations. Volume of solid = sum of volumes of individual parts. Surface area of combined solid = sum of exposed surface areas (not counting joined faces). Frustum of cone: V = (πh/3)(r₁² + r₁r₂ + r₂²), CSA = π(r₁+r₂)l.
Frustum CSA = π(r₁+r₂)l
Frustum TSA = π(r₁+r₂)l + π(r₁²+r₂²)
Frustum V = (πh/3)(r₁² + r₁r₂ + r₂²)
Frustum l = √[h² + (r₁−r₂)²]
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