Distance and Section Formula
Coordinate Geometry • Class 10 Mathematics • NCERT • CBSE
Distance formula: d = √[(x₂−x₁)² + (y₂−y₁)²]. Section formula (internal division): P(x,y) = ((m·x₂ + n·x₁)/(m+n), (m·y₂ + n·y₁)/(m+n)). Midpoint formula: M = ((x₁+x₂)/2, (y₁+y₂)/2).
Key Formulas
Distance: d = √[(x₂−x₁)² + (y₂−y₁)²]Section formula: P = ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n))Midpoint: M = ((x₁+x₂)/2, (y₁+y₂)/2)Area of triangle = ½|x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|
Frequently Asked Questions
- How do you derive the distance formula?
- The distance formula comes from Pythagoras' theorem. For two points A(x₁,y₁) and B(x₂,y₂), draw a right triangle: horizontal leg = |x₂ − x₁|, vertical leg = |y₂ − y₁|. By Pythagoras: AB² = (x₂−x₁)² + (y₂−y₁)², so AB = √[(x₂−x₁)² + (y₂−y₁)²].
- What is the section formula?
- The section formula gives the coordinates of a point P that divides line segment AB in ratio m:n internally. If A = (x₁,y₁) and B = (x₂,y₂), then P = ((mx₂ + nx₁)/(m+n), (my₂ + ny₁)/(m+n)). Special case: when m = n (midpoint), the formula simplifies to ((x₁+x₂)/2, (y₁+y₂)/2).
- How do you check if three points are collinear?
- Three points are collinear (lie on the same straight line) if the area of the triangle formed by them is zero. Formula: Area = ½|x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|. If this equals 0, the points are collinear. Alternatively, check if the slope between each pair of points is equal.
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